| An object at rest will remain at rest, and an object in motion will keep moving at the same speed in a straight line, unless it is acted on by some force. |
| Corpus omne perseverare in statu suo quiscendi vel movendi uniformiter in directum, nisi quatenus a viribus impressis cogitur statum illum mutare. cogo, cogere, coegi, coactum - (cum - ago) to bring together, drive, collect; restrict, compel nisi quatenus - except in so far as; unless |


N (that is, 100 N, to the right), and the other team could be exerting a force to the left of -100
N, canceling them out.
m/s² that says how strong gravity is on Earth, and that


| Material | ![]() | ![]() |
|---|---|---|
| glass-glass | 0.9 | 0.4 |
| metal-metal | .6 | .4 |
| greased metal | .1 | .05 |
+
form of a vector. Instead, we typically know the length of the vector, and what direction it points in. So for example, in a plane, I can know that I am going NE at 71 m/s; I am unlikey to have a speedometer that reads this out as (50
+ 50
) m/s.
and
components of
.sin(), cos(), and tan(). These functions allow us to find out the ratio between any two sides in a right triangle, given that we know the angles of the triangle.
a in a right triangle, and label the three sides as the Hypotenuse, the side Opposite the angle a, and the side Adjacent to it, then:sin(a) gives the ratio Opposite / Hypotenusecos(a) gives the ratio Adjacent / Hypotenusetan(a) gives the ratio Opposite / Adjacent
= 6 N, and that this force is at an angle of 30°. In order to add it to other forces, I have to find its
and
component form. So, I have a triangle where the Hypotenuse is 6 long, one angle is 30°, and I want to find the y, which is Opposite that angle, and the x, which is Adjacent to it. I simply write down the facts that I know about the trig ratios:


= (5.2
+ 3
) N. As you can see, all that I need to do to solve for any side in the triangle, given a side I know, is to write an equation representing the fact that "sine is the ratio of opposite to hypotenuse" or whatever, and solve that equation.tan(), so if you want, you can just forget for now that it exists.
is positive and the
is negative. I will measure the angle by holding a protractor near the string; this tells me that the angle between the force and vertical is 60°.
amd
components. I draw this triangle above the vector, so that it will include the angle I just found. Then, I just need to do a bit of trig to find the missing sides:


= (-34.6
+ 20
) N. Notice that I have made the
negative, because the vector goes toward the left.
= -20
N (a mass of 2 kg) and that
= 34.6
N is the other tension force.
and
components, respectively, of the angled force.)
and
components.
and the
direction, the forces balance.
= (-43.3
+ 25
). I know that
is straight down, only in the
component. So, the
component I just found must be balanced by the
of the other force; it should be 43.3
.


= (43.3
- 11.6
) N. Assuming that the bird is not accelerating, I know that all the forces should add up to zero:
+
+
= 0
+ 25
+ 43.3
- 11.6
+
= 0
+
= 0
= -14.4
, by pushing down or pulling up on the object.
| Force | Symbol | What is it? When it is there? | Direction is... | Size is... |
|---|---|---|---|---|
| Weight | ![]() | Anything on Earth is pulled downwards by Earth's gravity. | Straight down. | The object's weight, which doesn't change. |
| Normal | ![]() | Solid objects don't like other solid objects to try to go through them. Any time two objects are in contact, they push against each other. | Perpendicular to the surface. | Enough to balance force into surface. |
| Tension | ![]() | Present whenever a rope or string exerts a force on something. | Along the string. | Any strength, same at both ends of rope. |
| Friction | ![]() | When two surfaces are pressed against one another, friction resists them trying to slip. | Opposing the force or movement. | μFN (μ is different for every pair of surfaces) |
| Applied | ![]() | An "applied force" just means you're pushing something. | Any direction. | Any strength. |





), a rope fighting against stretching (
), two surfaces trying to grab old of each other (
).All forces exist as part of a pair of forces acting on two different objects. If the force on A from B is , the force on B from A will be - : a force of the same strength in the opposite direction. |
) is always present.
pushing objects apart.
pulling the objects together.
resisting this.
